Consider the circuit shown in figure. The switch S is closed for t. < O, and steady-state conditions are established. The switch is then open ed at t = 0. Then we have to find potential difference and current through each inductor for the instant immediately after t = 0.

According to me at steady state , we can replace inductor as a simple wire .

So equivalent resistance will be 2R

And current through battery would be V/2R

As we replaced inductor with a wire so the potential difference across it should be zero .

But the answer given as 3V/2 and V for L$_1$ and L $_2$ respctively .